Java Method: Sum of all the digits of a number

How to create a Java program which adds all the given digits of a number ?

If you are looking for this..... you came to the right place.
The above question can be solved easily by using the give Java Method on Digit Sum.

//METHOD FOR Digits SUM

    int addDigits (int n)
   {
        int sum=0;
        int dig;
        while(n>0){
            dig = n%10;
            sum=sum+dig;
            n= n/10;
        }
        return sum;
    }

/* 
 *example run1: int sum=addDigits(101);
 *this will give following output: 1+0+1=2
*example run2: int sim=addDigits(99);
 *output will be: 9+9=18
 */

If you want to explore more on this.... Try the following Java Program using the above Digit Sum Method :

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;

public class digitSum{
    public static void main( String arg[]) throws IOException {
        InputStreamReader istream = new InputStreamReader(System.in) ;
        BufferedReader bufRead = new BufferedReader(istream) ;
        System.out.println("------------ Java Method for Digits Sum ------------");
        for(int i=1;i>=0;i++){      //Used for try again condition
            int num=0;
            try{
                System.out.print("Enter Number: ");
                num = addDigits( Integer.parseInt( bufRead.readLine() ) );
            }catch ( Exception Number ){
                System.out.println("******** Illegal Input! ********");
                continue;
            }
            System.out.println("Output: "+num);
            System.out.print("press Enter to Try Again or press 'q' and than Enter for exit: ");
            String opp = bufRead.readLine();
            if(opp.equalsIgnoreCase("q")){
                System.out.println("Thank You for using this program            -Code Nirvana");
                break;
            }
        }
    }
    public static int addDigits (int n)
   {
        int sum=0;
        int dig;
        while(n>0){
            dig = n%10;
            sum=sum+dig;
            n= n/10;
        }
        return sum;
    }
}

Output :